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<title>Problem 2352. -- [BeiJing2011]database -- 衡阳八中OJ离线版-2012-02-29</title><center><h2>2352: [BeiJing2011]database</h2><span class=green>Time Limit: </span>5 Sec&nbsp;&nbsp;<span class=green>Memory Limit: </span>256 MB<br><span class=green>Submit: </span>11&nbsp;&nbsp;<span class=green>Solved: </span>4<br>[<a href='submitpage.php?id=2352'>Submit</a>][<a href='problemstatus.php?id=2352'>Status</a>][<a href='bbs.php?id=2352'>Discuss</a>]</center><h2>Description</h2><div class=content><p>在这个问题中，你需要设计一个简单的底层数据库。<br />
简单的说，你需要写一个程序支持以下三个函数：<br />
Init、CountPoint、InsertPoint。<br />
下面是实现细节：<br />
Init<br />
C语言函数原型：void Init()。<br />
Pascal语言函数原型：procedure Init。<br />
没有输入参数，没有返回值，仅在程序开始时被调用一次。<br />
CountPoint<br />
C语言函数原型：int CountPoint(int Leftside, int Rightside)<br />
Pascal语言函数原型：function CountPoint(Leftside,Rightside:longint):longint<br />
两个参数分别为查询的左右边界，你应该返回之前有多少个点在当前给定左右边界内，在边界上的点视为在边界内。<br />
参数类型：int/int(C/C++)，longint/longint(pascal)<br />
返回值类型：int(C/C++)，longint(pascal)<br />
InsertPoint<br />
C语言函数原型：void InsertPoint(int Position)<br />
Pascal语言函数原型：procedure InsertPoint(Position:longint)<br />
输入参数为插入的点的坐标。<br />
参数类型：int(C/C++)，longint(pascal)<br />
没有返回值</p>
<p>================================================================</p>
<p>本题已改成传统类型题,请自觉写在线算法</p></div><h2>Input</h2><div class=content></div><h2>Output</h2><div class=content></div><h2>Sample Input</h2>
			<div class=content><span class=sampledata>8<br />
0 0<br />
1 0 1<br />
0 1<br />
1 0 2<br />
0 2<br />
0 6<br />
1 2 6<br />
1 1 8<br />
</span></div><h2>Sample Output</h2>
			<div class=content><span class=sampledata>1<br />
2<br />
2<br />
3<br />
</span></div><h2>HINT</h2>
			<div class=content><p></p></div><h2>Source</h2>
			<div class=content><p><a href='problemset.html?search='></a></p></div><center>[<a href='submitpage.php?id=2352'>Submit</a>][<a href='problemstatus.php?id=2352'>Status</a>][<a href='bbs.php?id=2352'>Discuss</a>]</center>﻿<br>

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